Merge pull request #3294 from kevinzakka:mujoco-minimize-x-scale
PiperOrigin-RevId: 923519000 Change-Id: I4a8fa1f031428cf41d194d17ea4c41975f93f745
This commit is contained in:
+42
-11
@@ -156,6 +156,7 @@ def least_squares(
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output: Optional[TextIO] = None,
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iter_callback: Optional[Callable[[List[IterLog]], None]] = None,
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check_derivatives: bool = False,
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x_scale: Optional[Union[float, np.ndarray, str]] = None,
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) -> Tuple[np.ndarray, List[IterLog]]:
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"""Nonlinear Least Squares minimization with box bounds.
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@@ -178,6 +179,12 @@ def least_squares(
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output: Optional file or StringIO to which to print messages.
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iter_callback: Optional iteration callback, takes trace argument.
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check_derivatives: Compare user-defined Jacobian and norm against fin-diff.
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x_scale: Per-parameter scaling (matches scipy's x_scale). Setting
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x_scale=D solves the problem in the change of variables z = x / D
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and un-scales the result. None (default) or 1.0 is no scaling.
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'jac' sets D_i = 1 / ||J(:, i)|| at each iteration. An array of
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shape (n,) (or a positive scalar) is used as D directly. Note
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that mu, mu_min and mu_max then act on the scaled subproblem.
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Returns:
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x: best solution found
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@@ -203,6 +210,24 @@ def least_squares(
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mu = np.float64(0.0) # Optimistically start with no regularization.
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n_reduc = 0 # Number of sequential mu reductions.
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# Resolve x_scale -> D of shape (n, 1). For 'jac', D is refreshed each iter;
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# None means no scaling (D = 1).
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adaptive_scale = isinstance(x_scale, str)
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if adaptive_scale and x_scale != 'jac':
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raise ValueError(
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f"x_scale must be None, 'jac', a positive scalar, or array, got "
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f'{x_scale!r}.'
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)
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if x_scale is None or adaptive_scale:
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D = np.ones((n, 1))
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else:
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D = np.asarray(x_scale, dtype=np.float64)
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if D.shape not in ((), (n,)):
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raise ValueError(f'x_scale array must have shape ({n},), got {D.shape}.')
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if not np.all(np.isfinite(D)) or np.any(D <= 0):
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raise ValueError('x_scale must be positive and finite.')
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D = (np.ones(n) * D).reshape(n, 1)
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# Initialize logging.
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trace = []
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n_res = 0
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@@ -284,8 +309,13 @@ def least_squares(
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if i == 0 and check_derivatives and not isinstance(norm, Quadratic):
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check_norm(r, norm, eps, output)
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# Get gradient, Gauss-Newton Hessian.
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grad, hess = norm.grad_hess(r, jac)
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# Refresh D for adaptive ('jac') scaling: column-norm preconditioner.
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if adaptive_scale:
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col_norms = np.linalg.norm(jac, axis=0)
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D = (1.0 / np.maximum(col_norms, eps)).reshape(n, 1)
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# Gradient/Hessian in scaled coords (jac * D.T scales columns).
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grad, hess = norm.grad_hess(r, jac * D.T)
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# Get free (unclamped) gradient.
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if bounds is None:
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@@ -304,9 +334,9 @@ def least_squares(
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print('Zero gradient norm: exact minimum found?', file=output)
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break
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# Bounds relative to x
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dlower = None if bounds is None else bounds[0] - x
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dupper = None if bounds is None else bounds[1] - x
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# Bounds relative to x, expressed in scaled coords (dz = dx / D).
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dlower = None if bounds is None else (bounds[0] - x) / D
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dupper = None if bounds is None else (bounds[1] - x) / D
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# Find reduction satisfying Armijo's rule.
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armijo = -1
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@@ -329,8 +359,8 @@ def least_squares(
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if status != Status.MAX_ITER:
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break
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# New candidate, residual.
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xnew = x + dx
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# New candidate (D * dx is the x-space step).
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xnew = x + D * dx
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t_start = time.time()
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rnew = residual(xnew)
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t_res += time.time() - t_start
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@@ -362,8 +392,9 @@ def least_squares(
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else:
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reduction_ratio = reduction / expected_reduction
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# Iteration message.
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dx_norm = np.linalg.norm(dx)
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# Iteration message. Step printed in x-space (D * dx).
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step = D * dx
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dx_norm = np.linalg.norm(step)
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if verbose >= Verbosity.ITER.value:
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logmu = np.log10(mu) if mu > 0 else -np.inf
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message = (
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@@ -377,7 +408,7 @@ def least_squares(
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log = IterLog(candidate=x, objective=y, reduction=reduction, regularizer=mu)
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if verbose >= Verbosity.FULLITER.value:
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log = dataclasses.replace(
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log, residual=r, jacobian=jac, grad=grad, step=dx
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log, residual=r, jacobian=jac, grad=grad / D, step=step
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)
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trace.append(log)
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if iter_callback is not None:
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@@ -388,7 +419,7 @@ def least_squares(
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status = Status.DX_TOL
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break
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# Modify regularizer like in (Bazaraa, Sherali, and Shetty)
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# Modify regularizer like in (Fletcher, 1971)
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if reduction_ratio > 0.75:
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mu, n_reduc = decrease_mu(mu, n_reduc)
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elif reduction_ratio < 0.25:
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@@ -319,6 +319,110 @@ class MinimizeTest(absltest.TestCase):
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self.assertIn('User-provided norm gradient matches', out.getvalue())
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self.assertIn('User-provided norm Hessian matches', out.getvalue())
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def test_x_scale_default_is_no_op(self) -> None:
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"""x_scale=1.0 produces an identical trace to the default unscaled run."""
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def residual(x):
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return np.stack([1 - x[0, :], 10 * (x[1, :] - x[0, :] ** 2)])
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x0 = np.array((0.0, 0.0))
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x_default, trace_default = minimize.least_squares(
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x0, residual, verbose=minimize.Verbosity.SILENT)
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x_one, trace_one = minimize.least_squares(
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x0, residual, x_scale=1.0, verbose=minimize.Verbosity.SILENT)
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np.testing.assert_array_equal(x_default, x_one)
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self.assertEqual(len(trace_default), len(trace_one))
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def test_x_scale_reaches_same_minimum(self) -> None:
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"""Both 'jac' and an explicit array reach the unscaled run's minimum."""
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def residual(x):
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return np.stack([1 - x[0, :], 10 * (x[1, :] - x[0, :] ** 2)])
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x0 = np.array((0.0, 0.0))
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x_unscaled, _ = minimize.least_squares(
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x0, residual, verbose=minimize.Verbosity.SILENT)
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x_jac, _ = minimize.least_squares(
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x0, residual, x_scale='jac', verbose=minimize.Verbosity.SILENT)
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x_array, _ = minimize.least_squares(
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x0, residual, x_scale=np.array([10.0, 0.1]),
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verbose=minimize.Verbosity.SILENT)
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np.testing.assert_allclose(x_jac, x_unscaled, atol=1e-6)
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np.testing.assert_allclose(x_array, x_unscaled, atol=1e-6)
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def test_x_scale_validation(self) -> None:
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"""Invalid x_scale arguments raise ValueError."""
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def residual(x):
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return x
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x0 = np.array((1.0, 1.0))
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bad_values = [
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'bogus', # unknown string
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np.array([1.0, -1.0]), # non-positive entry
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np.array([np.inf, 1.0]), # non-finite entry
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np.array([1.0]), # wrong shape
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]
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for bad in bad_values:
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with self.assertRaises(ValueError):
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minimize.least_squares(
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x0, residual, x_scale=bad,
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verbose=minimize.Verbosity.SILENT)
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def test_x_scale_with_bounds(self) -> None:
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"""x_scale combined with bounds reaches the constrained optimum."""
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def residual(x):
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return np.stack([1 - x[0, :], 10 * (x[1, :] - x[0, :] ** 2)])
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x0 = np.array((2.0, 0.0))
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bounds = [np.array((1.5, -10.0)), np.array((10.0, 10.0))]
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expected = np.array([1.5, 2.25])
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# Without scaling.
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x_noscale, _ = minimize.least_squares(
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x0, residual, bounds=bounds, verbose=minimize.Verbosity.SILENT)
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np.testing.assert_allclose(x_noscale, expected, atol=1e-4)
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# With fixed x_scale array.
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x_scaled, _ = minimize.least_squares(
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x0, residual, bounds=bounds, x_scale=np.array([1.0, 1e-5]),
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verbose=minimize.Verbosity.SILENT)
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np.testing.assert_allclose(x_scaled, expected, atol=1e-4)
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# With adaptive x_scale='jac'.
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x_jac, _ = minimize.least_squares(
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x0, residual, bounds=bounds, x_scale='jac',
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verbose=minimize.Verbosity.SILENT)
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np.testing.assert_allclose(x_jac, expected, atol=1e-4)
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def test_x_scale_jac_convergence(self) -> None:
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"""'jac' scaling converges faster on Powell's badly scaled function."""
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# Powell's badly scaled function (Moré, Garbow, Hillstrom #3):
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# r1 = 1e4 * x1 * x2 - 1
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# r2 = exp(-x1) + exp(-x2) - 1.0001
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# The 1e4 multiplier creates Jacobian columns with wildly different
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# norms, making the unscaled LM regularizer ineffective.
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def residual(x):
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return np.stack([
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1e4 * x[0, :] * x[1, :] - 1,
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np.exp(-x[0, :]) + np.exp(-x[1, :]) - 1.0001,
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])
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x0 = np.array([0.0, 1.0])
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# Analytical solution: x1*x2 = 1e-4, exp(-x1)+exp(-x2) = 1.0001.
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x_star = np.array([1.098159e-5, 9.106146])
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x_default, trace_default = minimize.least_squares(
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x0, residual, verbose=minimize.Verbosity.SILENT, max_iter=400)
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x_jac, trace_jac = minimize.least_squares(
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x0, residual, x_scale='jac', verbose=minimize.Verbosity.SILENT)
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# Both reach the correct minimum.
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np.testing.assert_allclose(x_default, x_star, rtol=1e-4)
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np.testing.assert_allclose(x_jac, x_star, rtol=1e-4)
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# Without scaling the solver needs 331 iterations to converge.
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# With 'jac' scaling it converges in 55: a 6x improvement.
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self.assertGreater(len(trace_default) - 1, 300)
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self.assertLess(len(trace_jac) - 1, 70)
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if __name__ == '__main__':
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absltest.main()
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